Optimal. Leaf size=632 \[ -\frac{i b e \text{PolyLog}\left (2,-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{-\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}-\frac{i b e \text{PolyLog}\left (2,\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{-\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}-\frac{i b e \text{PolyLog}\left (2,-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}-\frac{i b e \text{PolyLog}\left (2,\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}+\frac{i b e \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{-\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{-\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}-\frac{e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}-\frac{2 e \log \left (1-e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{d^3}-\frac{a+b \sin ^{-1}(c x)}{2 d^2 x^2}+\frac{b c e \tan ^{-1}\left (\frac{x \sqrt{c^2 d+e}}{\sqrt{d} \sqrt{1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt{c^2 d+e}}-\frac{b c \sqrt{1-c^2 x^2}}{2 d^2 x} \]
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Rubi [A] time = 1.0447, antiderivative size = 632, normalized size of antiderivative = 1., number of steps used = 30, number of rules used = 13, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.619, Rules used = {4733, 4627, 264, 4625, 3717, 2190, 2279, 2391, 4729, 377, 205, 4741, 4521} \[ -\frac{i b e \text{PolyLog}\left (2,-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{-\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}-\frac{i b e \text{PolyLog}\left (2,\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{-\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}-\frac{i b e \text{PolyLog}\left (2,-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}-\frac{i b e \text{PolyLog}\left (2,\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}+\frac{i b e \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{-\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{-\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d+e}+i c \sqrt{-d}}\right )}{d^3}-\frac{e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}-\frac{2 e \log \left (1-e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{d^3}-\frac{a+b \sin ^{-1}(c x)}{2 d^2 x^2}+\frac{b c e \tan ^{-1}\left (\frac{x \sqrt{c^2 d+e}}{\sqrt{d} \sqrt{1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt{c^2 d+e}}-\frac{b c \sqrt{1-c^2 x^2}}{2 d^2 x} \]
Antiderivative was successfully verified.
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Rule 4733
Rule 4627
Rule 264
Rule 4625
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rule 4729
Rule 377
Rule 205
Rule 4741
Rule 4521
Rubi steps
\begin{align*} \int \frac{a+b \sin ^{-1}(c x)}{x^3 \left (d+e x^2\right )^2} \, dx &=\int \left (\frac{a+b \sin ^{-1}(c x)}{d^2 x^3}-\frac{2 e \left (a+b \sin ^{-1}(c x)\right )}{d^3 x}+\frac{e^2 x \left (a+b \sin ^{-1}(c x)\right )}{d^2 \left (d+e x^2\right )^2}+\frac{2 e^2 x \left (a+b \sin ^{-1}(c x)\right )}{d^3 \left (d+e x^2\right )}\right ) \, dx\\ &=\frac{\int \frac{a+b \sin ^{-1}(c x)}{x^3} \, dx}{d^2}-\frac{(2 e) \int \frac{a+b \sin ^{-1}(c x)}{x} \, dx}{d^3}+\frac{\left (2 e^2\right ) \int \frac{x \left (a+b \sin ^{-1}(c x)\right )}{d+e x^2} \, dx}{d^3}+\frac{e^2 \int \frac{x \left (a+b \sin ^{-1}(c x)\right )}{\left (d+e x^2\right )^2} \, dx}{d^2}\\ &=-\frac{a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac{e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac{(b c) \int \frac{1}{x^2 \sqrt{1-c^2 x^2}} \, dx}{2 d^2}-\frac{(2 e) \operatorname{Subst}\left (\int (a+b x) \cot (x) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac{(b c e) \int \frac{1}{\sqrt{1-c^2 x^2} \left (d+e x^2\right )} \, dx}{2 d^2}+\frac{\left (2 e^2\right ) \int \left (-\frac{a+b \sin ^{-1}(c x)}{2 \sqrt{e} \left (\sqrt{-d}-\sqrt{e} x\right )}+\frac{a+b \sin ^{-1}(c x)}{2 \sqrt{e} \left (\sqrt{-d}+\sqrt{e} x\right )}\right ) \, dx}{d^3}\\ &=-\frac{b c \sqrt{1-c^2 x^2}}{2 d^2 x}-\frac{a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac{e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac{i e \left (a+b \sin ^{-1}(c x)\right )^2}{b d^3}+\frac{(4 i e) \operatorname{Subst}\left (\int \frac{e^{2 i x} (a+b x)}{1-e^{2 i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac{(b c e) \operatorname{Subst}\left (\int \frac{1}{d-\left (-c^2 d-e\right ) x^2} \, dx,x,\frac{x}{\sqrt{1-c^2 x^2}}\right )}{2 d^2}-\frac{e^{3/2} \int \frac{a+b \sin ^{-1}(c x)}{\sqrt{-d}-\sqrt{e} x} \, dx}{d^3}+\frac{e^{3/2} \int \frac{a+b \sin ^{-1}(c x)}{\sqrt{-d}+\sqrt{e} x} \, dx}{d^3}\\ &=-\frac{b c \sqrt{1-c^2 x^2}}{2 d^2 x}-\frac{a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac{e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac{i e \left (a+b \sin ^{-1}(c x)\right )^2}{b d^3}+\frac{b c e \tan ^{-1}\left (\frac{\sqrt{c^2 d+e} x}{\sqrt{d} \sqrt{1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt{c^2 d+e}}-\frac{2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac{(2 b e) \operatorname{Subst}\left (\int \log \left (1-e^{2 i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac{e^{3/2} \operatorname{Subst}\left (\int \frac{(a+b x) \cos (x)}{c \sqrt{-d}-\sqrt{e} \sin (x)} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac{e^{3/2} \operatorname{Subst}\left (\int \frac{(a+b x) \cos (x)}{c \sqrt{-d}+\sqrt{e} \sin (x)} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}\\ &=-\frac{b c \sqrt{1-c^2 x^2}}{2 d^2 x}-\frac{a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac{e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac{b c e \tan ^{-1}\left (\frac{\sqrt{c^2 d+e} x}{\sqrt{d} \sqrt{1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt{c^2 d+e}}-\frac{2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}-\frac{(i b e) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i \sin ^{-1}(c x)}\right )}{d^3}-\frac{\left (i e^{3/2}\right ) \operatorname{Subst}\left (\int \frac{e^{i x} (a+b x)}{i c \sqrt{-d}-\sqrt{c^2 d+e}-\sqrt{e} e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac{\left (i e^{3/2}\right ) \operatorname{Subst}\left (\int \frac{e^{i x} (a+b x)}{i c \sqrt{-d}+\sqrt{c^2 d+e}-\sqrt{e} e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac{\left (i e^{3/2}\right ) \operatorname{Subst}\left (\int \frac{e^{i x} (a+b x)}{i c \sqrt{-d}-\sqrt{c^2 d+e}+\sqrt{e} e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}+\frac{\left (i e^{3/2}\right ) \operatorname{Subst}\left (\int \frac{e^{i x} (a+b x)}{i c \sqrt{-d}+\sqrt{c^2 d+e}+\sqrt{e} e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{d^3}\\ &=-\frac{b c \sqrt{1-c^2 x^2}}{2 d^2 x}-\frac{a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac{e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac{b c e \tan ^{-1}\left (\frac{\sqrt{c^2 d+e} x}{\sqrt{d} \sqrt{1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt{c^2 d+e}}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{d^3}-\frac{2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac{i b e \text{Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )}{d^3}-\frac{(b e) \operatorname{Subst}\left (\int \log \left (1-\frac{\sqrt{e} e^{i x}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac{(b e) \operatorname{Subst}\left (\int \log \left (1+\frac{\sqrt{e} e^{i x}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac{(b e) \operatorname{Subst}\left (\int \log \left (1-\frac{\sqrt{e} e^{i x}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}-\frac{(b e) \operatorname{Subst}\left (\int \log \left (1+\frac{\sqrt{e} e^{i x}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{d^3}\\ &=-\frac{b c \sqrt{1-c^2 x^2}}{2 d^2 x}-\frac{a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac{e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac{b c e \tan ^{-1}\left (\frac{\sqrt{c^2 d+e} x}{\sqrt{d} \sqrt{1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt{c^2 d+e}}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{d^3}-\frac{2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac{i b e \text{Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )}{d^3}+\frac{(i b e) \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{\sqrt{e} x}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{d^3}+\frac{(i b e) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{\sqrt{e} x}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{d^3}+\frac{(i b e) \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{\sqrt{e} x}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{d^3}+\frac{(i b e) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{\sqrt{e} x}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{d^3}\\ &=-\frac{b c \sqrt{1-c^2 x^2}}{2 d^2 x}-\frac{a+b \sin ^{-1}(c x)}{2 d^2 x^2}-\frac{e \left (a+b \sin ^{-1}(c x)\right )}{2 d^2 \left (d+e x^2\right )}+\frac{b c e \tan ^{-1}\left (\frac{\sqrt{c^2 d+e} x}{\sqrt{d} \sqrt{1-c^2 x^2}}\right )}{2 d^{5/2} \sqrt{c^2 d+e}}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{d^3}+\frac{e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1+\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{d^3}-\frac{2 e \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )}{d^3}-\frac{i b e \text{Li}_2\left (-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{d^3}-\frac{i b e \text{Li}_2\left (\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}-\sqrt{c^2 d+e}}\right )}{d^3}-\frac{i b e \text{Li}_2\left (-\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{d^3}-\frac{i b e \text{Li}_2\left (\frac{\sqrt{e} e^{i \sin ^{-1}(c x)}}{i c \sqrt{-d}+\sqrt{c^2 d+e}}\right )}{d^3}+\frac{i b e \text{Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )}{d^3}\\ \end{align*}
Mathematica [F] time = 5.8612, size = 0, normalized size = 0. \[ \int \frac{a+b \sin ^{-1}(c x)}{x^3 \left (d+e x^2\right )^2} \, dx \]
Verification is Not applicable to the result.
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Maple [C] time = 0.346, size = 679, normalized size = 1.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{2} \, a{\left (\frac{2 \, e x^{2} + d}{d^{2} e x^{4} + d^{3} x^{2}} - \frac{2 \, e \log \left (e x^{2} + d\right )}{d^{3}} + \frac{4 \, e \log \left (x\right )}{d^{3}}\right )} + b \int \frac{\arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )}{e^{2} x^{7} + 2 \, d e x^{5} + d^{2} x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b \arcsin \left (c x\right ) + a}{e^{2} x^{7} + 2 \, d e x^{5} + d^{2} x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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